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Duplicate of Review of Calculus Flashcards | StudBud
Duplicate of Review of Calculus
1 / 20
What is the formula for derivative of an inverse?
A
h'(x)=(g(x)f'(x)-f(x)g'(x))/[g(x)]
2
B
[f'(x)]'=1/f'(f
-1
(x))
C
f'(x)=g'(h(x))(h'(x))
D
h'(x)=f(x)g'(x)+g(x)f'(x)
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correct · 0:00
