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Integral Calculus
∫ xyzdx
∫ csc u du
Integral Calculus
30 terms
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Format of your Name - Lastname_(Initials) - Example (DELACRUZ_EM)
Flashcards
30 cards
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Practice quiz
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Questions
30
Answers
1
∫ csc u du
csc u cot u + c
ln sin u + c
ln cos u + c
sec u tan u + c
2
∫ xyzdx
x2yz + c
xy2z + c
xyz2 + c
none of the choices
3
DOUBLE INTEGRAL : ∫xdx from 0 to 3∫ ydy from -x to x
-1
0
1
2
4
DOUBLE INTEGRAL : ∫x
3
dx from 0 to 1 ∫ dy from 0 to 4
42
2
0
1
5
d / dx sin(x) =
- cos(x)
2sin (x)
cos(x)
-2sin (x)
6
DOUBLE INTEGRAL : ∫ydy from 1 to 2 ∫ x
3
dx from 0 to 2y
42
2
0
1
7
∫ xe
x
dx from 0 to 1
-1
1
e
0
8
Physically, integrating ∫ fx d(x) from a to b ( means finding the
area to the left of point a
area under the curve from a to b
area to the right of point b
area above the curve from a to b
9
d / dx cot(x) =
csc2 (x)
−csc2 (x)
csc(x) cot (x)
- csc(x) cot (x)
10
∫ cos x from 0 to π/2
0
1
undefined
-1
11
DOUBLE INTEGRAL : ∫dy/y from -1 to 1 ∫ dx/x from 0 to e
y
1
2
0
-1
12
To get the area of Vertical Strips what formula is applicable
∫∫ dx dy
∫∫ dy dx
∫∫ xdx dy
∫∫ ydx dy
13
∫ x - 5 dx from 0 to 2
-8
7
-7
8
14
∫ e
sin u
cos u du
-sin u + c
esin u + c
cos u + c
-ecos u + c
15
∫ sin (x) dx from 0 to π
0.086
2
-1
1
16
∫ ln e
x
dx
2x
2x2
x2∕2
2dx/x
17
∫ sec(x)dx =
ln ∣sec(x) + tan(x)∣ + C
ln ∣sec(x) - tan(x)∣ + C
ln ∣csc(x) - cot(x)∣ + C
ln ∣csc(x) + cot(x)∣ + C
18
sin(2x) =
2 sin(2x) cos(2x)
sin(2x) cos(2x)
2
2 sin(x) cos(x)
19
∫ (2y +1)
6
from 1 to 2
5424
4542
5244
4524
20
Find the x ordinate given the area of Horizontal Strips what formula is applicable
∫∫ ydx dy
∫∫ xdx dy
∫∫ dx dy
∫∫ dy dx
21
Integral Calculus is Ant Differentiation of Derivatives
Yes
Situational
No
Maybe
22
∫ sech u du
tan-1 (cosh u) + c
tanh-1 (cosh u) + c
tan-1 (sinh u) + c
tanh-1 (sinh u) + c
23
To get the area of Horizontal Strips what formula is applicable
∫∫ dy dx
∫∫ xdx dy
∫∫ ydx dy
∫∫ dx dy
24
∫ sec
2
u / tan u
ln sec u + c
tan2u + c
ln tan u + c
sec3 u + c
25
d / dx sec(x) =
sec(x) tan(x)
sec2(x)
tan2(x)
-sec(x) tan(x)
26
When the possible integration do not apply on all process what method will i use?
Integration by Parts
Double Intetration
Triple Integration
Volume and Area
27
∫ ln xdx =
x ln x − x + C
x ln2 x + x + C
ln x − x + C
x ln2 x − x + C
28
If the sum has a limit as the maximum diameter of subregion
Triple Integration
Differentiate
Double Integration
Single Integration
29
∫ dx / x lnx
ln x + c
2 ln x + x
ln (ln x) + c
ln (x) / x + c
30
The exact value of ∫ xe
x
dx from 0.2 to 22 is most nearly
11.807
19.611
14.034
7.8036
