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AP Calculus AB Review Part 1 Flashcards | StudBud
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AP Calculus AB Review Part 1
AP Calculus AB Review Part 1
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AP Calculus AB Review #calculus #math #ap #derivatives #integrals
Flashcards
15 cards
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Questions
15
Answers
1
Choose the correct answer: (d/dx)[e
2x
] =
2xe2x
2e2x
2xe2x-1
e2x
2
Choose the correct answer.
7/27
-25/27
25/27
-7/27
3
Choose the correct answer: (d/dx)[sin(u)] =
tan(u)·u'
csc(u)·u'
cos(u)·u'
-cos(u)·u'
4
What does a derivative represent in calculus?
B) The total area under the curve.
A) The slope of the tangent line at a point on the curve.
D) The maximum value of a function.
C) The distance between two points on the curve.
5
Choose the correct answer: (d/dx)[h(x)*m(x)] =
h'(x)m(x) - h(x)m'(x)
h'(x)m(x) + h(x)m'(x)
h'(x)m'(x)
m'(x)h(x) - m(x)h'(x)
6
To find position from acceleration, you must...
find the 2nd derivative
integrate twice
find the 1st derivative
integrate once
7
Find the lim
x→0
(sin
x
/ 2x)
1/2
0
-1
-2
8
Choose the correct answer: (d/dx)[
u/v
] =
uv' + vu'
(uv') / (vu')
uv' - vu'
(vu' - uv')/(v2)
9
Choose the correct answer.
36
6
2
4
10
Choose the correct answer: (d/dx)[sec(u)] =
-csc(u)cot(u)·u'
-csc(u)tan(u)·u'
sec(u)tan(u)·u'
sec(u)cot(u)·u'
11
Using properties of definite integrals...
3
-11
-3
11
12
Choose the correct answer: (d/dx)[tan(u)] =
csc(u)·u'
-csc2(u)·u'
sec(u)·u'
sec2(u)·u'
13
Choose the correct answer: (d/dx)[cos(u)] =
-sin(u)·u'
cos2(u)·u'
sin(u)·u'
csc(u)·u'
14
Choose the correct answer.
-1
-3
3
1
15
Choose the correct answer.
-6x2sin(x3)
6x2sin(x3)cos(x3)
6x2cos(x3)
-6x2sin(x3)cos(x3)