Yr9 Algebra Basics Recap (Ex 2A-E)

1-\left(4a-6\right)=

\left(h+k\right)\div9 Can be written as

22x-45=93 To solve this equation, you would first:

5a^2\left(2a^3+3ab\right)=10a^5+15a^2b

\left(3a+2\right)+\left(3a+2\right)+\left(3a+2\right)=

\frac{a-2}{4}=7 The first step to undo the operations is to divide both sides by 4.

\frac{b-2}{8}=1 The solution to this equation is:

6a\times3m\times2b=

r\left(r^6-9\right)=r^7-9r

-\left(q+7\right) could be written as

An algebraic expression for "subtract 17 from an unknown number and then triple your answer"

\frac{a}{4}+3=7 The first step to undo the operations is to subtract 3 from both sides

\frac{1}{2}\left(6u-8\right)=3u-4

z=8 if, 2z=16

Evaluate a-b

15mn+2nm-5mn

The next line when you divide both sides of the eqauation by 7 is 7\left(m+21\right)=14