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Duplicate of Derivatives: product and quotient rules Flashcards | StudBud
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Duplicate of Derivatives: product and quotient rules
Duplicate of Derivatives: product and quotient rules
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Calculus derivatives using power, product, and quotient rules
Flashcards
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Questions
10
Answers
1
f(x)= 4x
2
+ tanx , find f'(x)
8x + sec2x
4x+sec2x
8x+ secx
-8+csc2x
2
If y=2√x -1 /(2√x) , then the derivative y' is
x + 1/(x√x)
4/√x + 1/(x√x)
1/√x + 1/(x√x)
1/√x + 1/(4x√x)
3
If f(5)=1, f'(5)=6, g(5)=-3, and g'(5)=2, calculate (f/g)' (5)
-20/9
-20
20/9
20
4
Give an equation for the tangent line to y=2x/(x+1) at the point (1, 1)
y-1 =2 (x-1)
y-1 = -2 (x-1)
y-1=1/2 (x-1)
y-1 = -1/2 (x-1)
5
If y = (3x
2
+ x)/(2x+1) then dy/dx =
(6x2+10x+1)/(2x+1)2
(12x2+6x+1)/(2x+1)2
(6x2+6x+1)/(2x+1)2
(9x2+6x+1)/(2x+1)2
6
The slope of the curve y=6x
1/2
+x at x = 4
4
3/2
7/2
5/2
7
if y=x
4
e
x
, then dy/dx =
4x3ex + x4
4x3ex
4x3ex + x4ex
4xex + x4ex
8
The position of particle is s(t)=2t
3
-7t
2
+4t+1 meters. Find the velocity at t = 2 sec
4 m/s
-4 m/s
0 m/s
16 m/s
9
If y=(x-3) / (2-5x) , then dy ∕ dx =
13 / ((2-5x)2
(17-10x)/(2-5x)2
(x-3) / ((2-5x)2
-13 / (2-5x)2
10
f(x)= 1/x - x^2
(1/x^2) - 2x
(-1/2)x1/2 -2x
(-1/x^2) - 2x
(1/2)x1/2 -2x