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Index rule
Evaluate 82=
Simplify 6a4b5×(2/3)ab3
Index rule
17 terms
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Basics of algebra
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Questions
17
Answers
1
Simplify 6a
4
b
5
×(2/3)ab
3
12a5b6
6a9b4
4a5b8
8/3a4b15
2
Evaluate 8
2
=
6
10
16
64
3
Evaluate 125
1/3
=
5
8
6
7
4
Simplify 3p
4
q
3
÷(1/5)pq
2
=
15p5q4
45 p4q5
(3/5)p5q2
15p3q
5
Evaluate 4×√6×√6=
4√6
5√6
36
24
6
Evaluate -5
3
=
-125
15
-15
125
7
Evaluate (-2)
-4
=
-6
16
1/16
-8
8
Evaluate (4/9)
1/2
=
3/2
4/3
2/3
2/4
9
Simplify 6x
5
y
8
÷3x
2
y=
2x3y7
18x7y9
3x5y7
2x7y8
10
Evaluate 3
-2
=
-1/9
6
-6
1/9
11
Simplify 2p
2
×4p
5
=
6p7
2p-3
4p8
8p7
12
Work out √49=
14
7
6
12
13
Evaluate √5×√5=
√10
2√5
25
5
14
Work out √121=
12
9
11
10
15
Evaluate (2/5)
0
=
2
1
0
0.4
16
Work out 4
1/2
×27
1/3
=
18
1081/6
6
181/2
17
Work out (y
3
)
4
=
y12
4y3
y7
y
