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Multivariable Calculus: Space Figures & Partial Derivatives Test Review Flashcards | StudBud
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Multivariable Calculus: Space Figures & Partial Derivatives Test Review
Multivariable Calculus: Space Figures & Partial Derivatives Test Review
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#MVC #multivariable #partialderivatives
Flashcards
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Questions
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Answers
1
A gradient at a point will behave
how
relative to a level curve?
perpendicular
any direction
parallel
tangent
2
The directional derivative of z = (x
2
)(e
-y
) at the point (-1,0) in the direction of (4,-3) is
-11/5
-3/5
-5
-1
3
Which equation below gives the graph of this quadric surface?
x2 + 2z2 -6x - y + 10 = 0
4x2- y2 - z + 8x + 8z + 24 = 0
I don't know!
4x2 - y2 + 2z2 + 4 = 0
4
See question...
16 and 8
12 and -8
12 and 8
8 and 16
5
A gradient points in what direction?
maximum rate of change
tangent to the curve
toward the center
up
6
Given f(x,y) below and x = sin(2t) and y = cos t, find df/dt when t = 0.
6
3
0
-6
7
Clairaut's Theorem states that _____
fx = fy
fxy = fyx
fxx = fyy
fxy = fxx
8
∇f(x, y), where f(x, y) = 10x
5
y is
<5x6/3, y2/2>
<10x5, y>
<50x4, 10x5>
<50x4y, 10x5>
9
A gradient is a(n) _____
vector
number
scalar
integral
10
Find the domain & range of f(x,y,z) = √(4 - x
2
-y
2
-z
2
).
x2+y2+y2 ≥ 4, 0 ≤ w ≤ 2
x2+y2+y2 ≤ 4, 0 ≤ w
x2+y2+y2 ≤ 4, 0 ≤ w ≤ 2
x2+y2+y2 ≥ 4, 0 ≤ w
11
The "D" in the multivariable second derivative test is:
fxxfyy(fxy)2
fxxfyy - fxy
fxxfyy - (fxy)2
fxxfyy + (fxy)2
12
If f
xx
f
yy
- (f
xy
)
2
< 0, this means . . .
No solution
its time to move on.
there is a rel. extremum
saddle point
13
Find the equation of the tangent plane to the surface
z + 7 = xe
y
cos(z)
at the point
(7,0,0)
.
x + 7y + z = 7
7x + y - z = 7
x + 7y - z = 7
x + y - 7z = 7
14
Is fxy at P positive or negative?
positive
0
negative
15
At what pt. does the following function have a local max:
f(x,y) = 3 - 10x + 12y - 5x
2
- 6y
2
(1,1)
(-1,1)
(0,1)
(3,1)
16
Given f(x, y, z) = x
30
y
26
z, what is f
xyzyzzyyxx
?
2360x27y22
4320x27y22
0
85700x27y22
17
A Pringle
TM
is an example of a(n) _____
hyperbolic paraboloid
all of the above
a surface with a saddlepoint
potato chip
18
Find the equation of the tangent plane to f(x,y) = (e
x
)(cos y) at the point (0,0,1).
z = x + y + 1
z = 2x + y
z = y + 1
z = x + 1