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Duplicate of Calculus Chapter 3 Flashcards | StudBud
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Duplicate of Calculus Chapter 3
Duplicate of Calculus Chapter 3
19 terms
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Calculus -- Derivatives #calculus
Flashcards
19 cards
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Questions
19
Answers
1
This function is not differentiable at x = 0 because there is a . . . .
corner
cusp
discontinuity
vertical tangent
2
The Quotient Rule: "low d-hi minus hi d-low over ______ squared."
c
x
low
high
3
This function is not differentiable at x = 0 because there is a . . . .
corner
vertical tangent
discontinuity
cusp
4
Differentiate the function below . . .
y' = -3
y' = -6x
y' = -6x2
y' = -3x3
5
Differentiate the function below . . .
y' = tanx + cotx
y' = cosx - sinx
y' = sinx + cosx
y' = 7
6
This function is not differentiable at x = 0 because there is a . . . .
discontinuity
corner
vertical tangnent
cusp
7
True or False: A function can be continuous but not differentiable at a point.
True
False
8
Differentiate the function below . . .
y' = -csc2x
y' = sec2x
y' = -cscxcotx
y' = cotx
9
The absolute value of velocity is . . . .
nice
speed
negative
acceleration
10
To differentiate the function y = 2xsinx we have to use the . . . .
Product Rule
Power Rule
Produce Rule
Quotient Rule
11
Differentiate the function below . . .
y' = sec2x
y' = cscxcotx
y' = secxtanx
y' = -cos2x
12
The graph of the derivative of the function below would look like . . . .
a horizontal line
a non-horizontal line
a parabola
Hunter Austing
13
If s(t) is the position function of an object, the second derivative of s(t) gives us . . . .
velocity
acceleration
speed
2 headaches
14
Differentiate the function below . . .
y' = -sinx
y' = -cot2x
y' = cscxcotx
y' = -csc2x
15
This is the . . . .
Power Rule
Definition of the Derivative
Alternate Definition of the Derivative
Quotient Rule
16
The graph of the derivative of a function f(x) describes the _____ of f(x).
symmetry
life
asymptotes
slope
17
If s(t) is the position function of an object, the first derivative of s(t) gives us . . . .
acceleration
velocity
a headache
speed
18
Differentiate the function below . . .
y' = sec2x
y' = secxtanx
y' = cotx
y' = -csc2x
19
To find a horizontal tangent to a function f, take its derivative and . . .
set it equal to 0
set it equal to 1
run
simplify