Find the equation for the tangent line at the given point.
- y-\frac{2\pi}{3}=-8\left(x+\frac{\sqrt{3}}{10}\right)
- y-\frac{\pi}{3}=-8\left(x+\frac{\sqrt{3}}{10}\right)
- y+\frac{\pi}{6}=-10\left(x+\frac{\sqrt{3}}{10}\right)
- y-\frac{5\pi}{6}=-10\left(x+\frac{\sqrt{3}}{10}\right)