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Calculus: Derivatives Flashcards | StudBud

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[cot-1(3x)]' =

csc(3x)' =

Calculus: Derivatives

15 terms·StudBud Administration·195 plays

Differentiation patterns in Calculus

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Questions 15

Answers

1
csc(3x)' =
csc(3x) cot(3x)
3 csc(3x) cot(3x)
-3 csc(3x) cot(3x)
-3 csc2(3x)
2
[cot^-1(3x)]' =
3 / [ 1 + 9x2 ]
- 3 csc2(3x)
- 3 / [ 1 + 9x2 ]
3 csc2(3x)
3
[ ln(sin 3x) ]' =
cot(3x)
1 / sin(3x)
3 tan(3x)
3 cot(3x)
4
(1/3 x⁶)' =
2 x6
6x5
x5
2 x5
5
(e^πx)' =
π eπ(x-1)
1/π eπx
eπx
πeπx
6
(sec^-1x)' =
sec(x) tan(x)
1 / [ |x| √(x2-1) ]
1 / √(1 - x2)
1 / (1+x2)
7
(log₇x)' =
ln(7) / x
ln(x) / ln(7)
x / ln(7)
1 / [ x ln(7) ]
8
(sin^-1x)' =
1 / [ |x| √(x2-1) ]
1 / √(1 - x2)
1 / (1+x2)
cos(x)
9
ln(x)' =
1
1 / x
ex
x
10
(4^{cos 3x})' =
4cos 3x ( 3 sin 3x) / (ln 4)
4cos 3x ( -3 sin 3x) / (ln 4)
4cos 3x ( 3 sin 3x) (ln 4)
4cos 3x ( -3 sin 3x) (ln 4)
11
cos(3x)' =
-3sin(3x)
-1/3 sin(3x)
sin(3x)
1/3 sin(3x)
12
(tan^-1x)' =
1 / [ |x| √(x2-1) ]
sec2x
1 / (1+x2)
1 / √(1 - x2)
13
(4^x)' =
4x ln 4
4x
4x ln x
x 4x-1
14
sec(3x)' =
sec(3x) tan(3x)
3 sec(3x) tan(3x)
-3 sec(3x) tan(3x)
- sec(3x) tan(3x)
15
tan(3x)' =
sec2(3x)
- sec2(3x)
-3 sec2(3x)
3 sec2(3x)