Duplicate of AP Calculus Test Review 1 Flashcards

1

d/dx tan(2x) =

sec(2x)tan(2x)
2sec2(2x)
2sec2(x)
sec2(2x)

2

d/dt e²πt =

e2π
2e2πt
e2πt
0

3

f(x) = |x| f'(4) =

1
0
x
4

4

If a function is continuous, must it be differentiable?

?
no
yes
BUST IT!

5

f(x) = sin x f''(x)=

- cos x
- sin x
cos x
sin x

6

f(x) = |x| f''(5) =

-1
undefined
1
0

7

∫sec x dx =

-ln |secx + tanx| + c
secxtanx + c
ln |secx + tanx| + c
ln |secxtanx| + c

8

If a function is differentiable, must it be continuos?

no
only if there is no cusp
sometimes
yes

9

∫e^4xdx =

¼e4x + c
¼e4x
4e4x + c
e4x + c

10

d/dx csc(x²) =

-2xcsc(x2)cot(x2)
2xcsc(x2)cot(x2)
-2xcsc(x)cot(x)
-csc(x2)cot(x2)

11

∫cot(2x)dx =

½ln|sin(2x)| + c
½ln|cos(2x)| + c
-ln|sin(2x)| + c
2ln|sin(2x)| + c

12

y = |x| y'(0) =

does not exist
1
0
-1

13

d/dx ln (√x) =

1/(x2)
1/(2x)
2/x
1/x

14

y = e^cosx y'=

e-sinx
(sinx)esinx
(-sinx)ecosx
(sinx)ecosx

15

f(x) = |x| f'(-88.8) =

-88.8
0
1
-1

16

When is a continuous function not differentiable?

At a cusp
At a cusp or asymptote
At an asymptote
At a hole

17

d/dx sec x =

secxtanx
tan2x
sec2x
sexytan

18

If v(4) = 5 and a(4) = -2, how is the particle moving at time t = 4?

forward, speed decreasing
backward, speed decreasing
forward, speed increasing
backward, speed increasing

19

∫tanxdx =

-ln|cosx| + c
ln|cosx| + c
sec2x+c
-ln|sinx| + c

20

If v(2) = -6 and a(2) = -2, how is the particle moving at time t = 2?

forward, speed increasing
forward, speed decreasing
backward, speed decreasing
backward, speed increasing

Duplicate of AP Calculus Test Review 1

Questions 20

Duplicate of AP Calculus Test Review 1

Questions 20