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Duplicate of AP Calculus AB Review
Duplicate of AP Calculus AB Review
42 terms
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AP Calculus AB Review
Flashcards
42 cards
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Questions
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Answers
1
Choose the correct answer: (d/dx)[
u/v
] =
uv' - vu'
uv' + vu'
(uv') / (vu')
(vu' - uv')/(v2)
2
Choose the correct answer: (d/dx)[cos(u)] =
-sin(u)·u'
cos2(u)·u'
sin(u)·u'
csc(u)·u'
3
Choose the correct answer: (d/dx)[sec(u)] =
sec(u)cot(u)·u'
-csc(u)tan(u)·u'
sec(u)tan(u)·u'
-csc(u)cot(u)·u'
4
Choose the correct answer: ∫csc(x)cot(x)
dx
-cot2(x) + C
-csc(x) + C
sec(x) + C
cot(x) + C
5
Choose the correct answer.
All values of x
-3 < x < 1
-1 < x < 3
x < -1 and x > 3
6
Choose the correct answer: (d/dx)[
vu
] =
(uv') / (vu')
uv' - vu'
uv' + vu'
u'v'
7
Choose the correct answer: ∫sec
2
(x)
dx
tan(x) + C
sin(x)cos(x) + C
cot2(x) + C
sin(x) + C
8
Choose the correct answer: ∫a
x
dx
xln(a) + C
2x-2 + C
aln∣x∣ + C
ax / ln(a) + C
9
Choose the correct answer: ∫(1/x)
dx
2x-2 + C
ln∣x∣ + C
x<span style="font-size: 13.3333330154419px;">n+1 + C</span>
x-2 + C
10
Choose the correct answer: ∫
e
x
dx
ex
ex + C
xex + C
xex
11
Choose the correct answer: (d/dx)[tan(u)] =
csc(u)·u'
sec2(u)·u'
-csc2(u)·u'
sec(u)·u'
12
Choose the correct answer: ∫cos(x)
dx
sec(x) + C
sin(x) + C
-sin(x) + C
cot2(x) + C
13
Choose the correct answer: ∫sec(x)tan(x)
dx
cot2(x) + C
sec2(x) + C
sec(x) + C
tan(x) + C
14
Choose the correct answer.
28/3
32/3
14/3
16/3
15
For all related rates problems, you must derive each term with respect to
volume
time
area
x
16
Choose the correct answer.
2
4
36
6
17
Choose the correct answer.
7/27
-7/27
25/27
-25/27
18
Choose the correct answer: (d/dx)[
ln(u)
] =
(1/u)·u'
ln(u)·u'
(1/u)∙ln(u)·u'
ueu·u'
19
Choose the correct answer.
0
1
e+1
e-1
20
Choose the correct answer: (d/dx)[cot(u)] =
-csc(u)tan(u)·u'
sec2(u)·u'
sec(u)tan(u)·u'
-csc2(u)·u'
21
Choose the correct answer: ∫csc
2
(x)
dx
sec(x) + C
sin(x) + C
-cot2(x) + C
-cot(x) + C
22
Choose the correct answer: (d/dx)[sin(u)] =
tan(u)·u'
-cos(u)·u'
csc(u)·u'
cos(u)·u'
23
To find position from acceleration, you must...
integrate twice
find the 2nd derivative
integrate once
find the 1st derivative
24
What method is used to find volume?
Newton's method
L'Hopital's method
washer or shell method
Pascal's method
25
Choose the correct answer.
6x2cos(x3)
6x2sin(x3)cos(x3)
-6x2sin(x3)cos(x3)
-6x2sin(x3)
26
How do you find the area between two functions of x?
top - bottom
∫(top - bottom)dx
π(top + bottom)
∫(bottom - top)dx
27
Choose the correct answer: (d/dx)[
e
u
] =
ueu·u'
eu·u'
ueu
eu + C
28
The second derivative of a function provides information about the _______ of that function.
slope
speed
acceleration
concavity
29
Choose the correct answer.
-1
1
3
-3
30
Choose the correct answer.
7
6
2
4
31
Choose the correct answer.
e-t + C
e(-t/2) + C
e(t/2) + C
2e(t/2) + C
32
Choose the correct answer: ∫sin(x)
dx
-cos(x) + C
sin(x)cos(x) + C
cos(x) + C
cos2(x) + C
33
Choose the correct answer.
14
8
13
11
34
Choose the correct answer.
y -1= -2(x - π/4)
y = 2(x - π/4)
y = -2(x - π/4)
y-1 = 2(x - π/4)
35
Choose the correct answer: (d/dx)[sec(u)] =
sec(u)tan(u)·u'
sec(u)cot(u)·u'
-csc(u)cot(u)·u'
-csc(u)tan(u)·u'
36
Choose the correct answer: (d/dx)[
a
u
] =
ln(a)·u'
au·ln(u)·u'
au·u'
au·ln(a)·u'
37
Find the lim
x→0
(
sin
x
/ 2x)
-1
1/2
0
-2
38
The first derivative of a function provides information about the _______ of that function.
speed
slope
acceleration
concavity
39
What does the mean value theorem state (for continuous, differentiable functions)?
average slope = instantaneous slope
Average slope < 0
average slope > 0
average slope ≠ instantaneous slope
40
To find velocity from position, you must...
integrate once
integrate twice
find the 1st derivative
find the 2nd derivative
41
Choose the correct answer: (d/dx)[csc(u)] =
csc(u)cot(u)·u'
sec2(u)·u'
-csc(u)tan(u)·u'
-csc(u)cot(u)·u'
42
Choose the correct answer.
8π/3
16π/3
4π/3
32π/5