If g\left(x\right)=3x^2+2and f\left(x\right)=\frac{x+1}{x}, what is g(f(x))?
- g\left(f\left(x\right)\right)=3\left(\frac{x+1}{x}\right)^2+2
- g\left(f\left(x\right)\right)=\frac{3x^2+5}{x+2}
- g\left(f\left(x\right)\right)=\frac{3x^2+3}{3x^2+2}
- g\left(f\left(x\right)\right)=1