stud
bud
Sign up
Log in
Home
Library
Explore
SAT
More
Duplicate of Calculus Chapter 3 Flashcards | StudBud
Explore
/
Duplicate of Calculus Chapter 3
Duplicate of Calculus Chapter 3
19 terms
·
StudBud Administration
Calculus -- Derivatives #calculus
Flashcards
19 cards
F
Practice quiz
P
Host live
L
Questions
19
Answers
1
Differentiate the function below . . .
y' = -sinx
y' = -cot2x
y' = -csc2x
y' = cscxcotx
2
Differentiate the function below . . .
y' = cscxcotx
y' = secxtanx
y' = -cos2x
y' = sec2x
3
To find a horizontal tangent to a function f, take its derivative and . . .
run
set it equal to 1
set it equal to 0
simplify
4
Differentiate the function below . . .
y' = sinx + cosx
y' = tanx + cotx
y' = cosx - sinx
y' = 7
5
This function is not differentiable at x = 0 because there is a . . . .
cusp
vertical tangent
discontinuity
corner
6
True or False: A function can be continuous but not differentiable at a point.
True
False
7
The graph of the derivative of the function below would look like . . . .
a horizontal line
a parabola
a non-horizontal line
Hunter Austing
8
The graph of the derivative of a function f(x) describes the _____ of f(x).
slope
asymptotes
life
symmetry
9
To differentiate the function y = 2xsinx we have to use the . . . .
Produce Rule
Quotient Rule
Product Rule
Power Rule
10
If s(t) is the position function of an object, the first derivative of s(t) gives us . . . .
speed
acceleration
velocity
a headache
11
This function is not differentiable at x = 0 because there is a . . . .
corner
discontinuity
cusp
vertical tangent
12
If s(t) is the position function of an object, the second derivative of s(t) gives us . . . .
velocity
acceleration
2 headaches
speed
13
This function is not differentiable at x = 0 because there is a . . . .
vertical tangnent
corner
cusp
discontinuity
14
Differentiate the function below . . .
y' = -6x
y' = -3
y' = -3x3
y' = -6x2
15
This is the . . . .
Power Rule
Definition of the Derivative
Quotient Rule
Alternate Definition of the Derivative
16
Differentiate the function below . . . .
y' = 5x4
y' = 5x
y' = 4x5
y' = x4
17
Differentiate the function below . . .
y' = sec2x
y' = cotx
y' = -cscxcotx
y' = -csc2x
18
The absolute value of velocity is . . . .
negative
nice
acceleration
speed
19
Differentiate the function below . . .
y' = -csc2x
y' = cotx
y' = secxtanx
y' = sec2x