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4.4 Day 2 or 3 with Calculus-Optimization Flashcards | StudBud
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4.4 Day 2 or 3 with Calculus-Optimization
4.4 Day 2 or 3 with Calculus-Optimization
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read problems and find equation to be maximized or minimized.
Flashcards
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Questions
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Answers
1
What is the correct equation to be maximized?
x+y=9
P=xy2
xy=9
P=xy
2
What is the first step to solving an optimization problem?
Optimize
Find the derivative
Identify given quantities, write the equation to optimize
Verify
3
Which is the correct equation to me optimized?
4xy=48-x2
V=x2y
A=x2y
V=xy
4
What equation is to be maximized?
500=xy
A=xy
A=5x+2y
500=5x+2y
5
What is the final step in an optimization problem?
Verify
Answer the question
Write the equation
Find the second derivative
6
What equations are needed, in general, to solve an optimization problem?
One to be optimized, and one supplementary
One to be minimized
An equation to be maximized
7
How can you verify a max or min?
IDK
Use the second derivative test
Use test intervals of the first derivative
Look at the domain
8
Which is the equation to be optimized?
V=lwh
A=xy
P=x+y
9
Optimization is an application of
Area
Derivatives
Calculus
Integrals