An equation for this graph is

y = 4 sin (x) + 3, y = 4 cos (x - π/2) + 3

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Trig Review

21 termsStudBud Administration14 plays

Review #trigonometry #trig for the end of the chapter/year. Includes triangles, coordinate plane, unit circle, and functions.

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Questions 21

Answers

1
The midline of this graph is
y = 3
x = π / 2
y = 0
x = 0
2
The point (x, y) is how far from (0, 0)
r = √(x2 + y2)
r = x2 + y2
r = √(x + y)
r = x + y
3
An angle of 87° is in
Quadrant 3
Quadrant 1
Quadrant 2
Quadrant 4
4
The function graphed is ...
y = cot (x)
y = csc (x)
y = tan (x)
y = sin (x)
5
Solving this triangle requires ...
Luck and Prayer
The Law of Sines
SOH CAH TOA
The Law of Cosines
6
An equation for this graph is
y = 4 sin (x) + 3
y = 4 sin (x + 3)
y = 4 cos (x + 3) - π/2
y = 4 cos (x - π/2) + 3
7
An angle of 487° is in
Quadrant 1
Quadrant 4
Quadrant 2
Quadrant 3
8
The amplitude of this graph is
8
-1
7
4
9
An angle of (- 2π / 3) radians is in
Quadrant 4
Quadrant 1
Quadrant 2
Quadrant 3
10
cos (5π / 6) =
√3 / 2
1 / 2
- √3 / 2
- 1 / 2
11
tan (π / 3) =
- √3 / 3
- √3
√3 / 3
√3
12
On the Coordinate Plane, sin (θ) =
x / r
x
y / r
y
13
Solving this triangle requires ...
The Law of Sines
Luck and Prayer
The Law of Cosines
SOH CAH TOA
14
Solving this triangle requires ...
SOH CAH TOA
The Law of Cosines
The Law of Sines
Luck and Prayer
15
sin (3π / 4) =
√3 / 2
√2 / 2
- √3 / 2
- √2 / 2
16
The function graphed is ...
y = sin (x)
y = cos (x)
y = tan (x)
y = sec (x)
17
The function graphed is ...
y = cos (x)
y = sec (x)
y = sin (x)
y = tan (x)
18
The function graphed is ...
y = cot (x)
y = csc (x)
y = sec (x)
y = tan (x)
19
In a right triangle, sin (θ) = 3/5. What is cos (θ) ?
4/5
3/4
3/5
4/3
20
Solving this triangle requires ...
The Law of Sines
SOH CAH TOA
Luck and Prayer
The Law of Cosines
21
Ready to go?
I have mastered all three sides of this story.
Gettin' triggy with it.
I can trig with the best of them.
I am a trigonometry rock star.

Trig Review Flashcards | StudBud