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Trigonometry Review Flashcards | StudBud
Trigonometry Review
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How would the
inverse sine
of 7/14 be written?
A
sinθ=\frac{7}{14}
B
sin^{-1}(\frac{7}{14})=θ
C
sin^{-1}θ=\frac{7}{14}
D
sin\left(\frac{7}{14}\right)=θ
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