stud
bud
Sign up
Log in
Home
Library
Explore
SAT
More
AP Calculus Unit 3 - Advanced Derivatives Flashcards | StudBud
Explore
/
AP Calculus Unit 3 - Advanced Derivatives
AP Calculus Unit 3 - Advanced Derivatives
13 terms
·
StudBud Administration
·
337 plays
#calculus
Flashcards
13 cards
F
Practice quiz
P
Host live
L
Questions
13
Answers
1
The derivative of y = tan
-1
(x
2
) is . . . . .
-1\sec^{-2}\left(x^2\right)2x
\frac{1}{1+x^4}
\frac{2}{1+x^3}
\frac{2x}{1+x^4}
2
To differentiate y = cos(x
2
) what are we seeing?
Implicit Rule
Product Rule
Chain Rule
Quotient Rule
3
When using implicit differentiation, each time we differentiate y we multiply by . . . .
0
1
dy/dx
dx/dy
4
The derivative of 5sec(x) is . . . .
5tan2(x)
5sec2(x)
5sec(x)tan(x)
0
5
The derivative of y = 4x
e+3
is . . . .
4e+3
4
(e + 3)4xe+2
(e + 3)4x
6
The derivative of y = sin
-1
(x) is . . . .
\frac{x}{\sqrt{1+x^2}}
cos-1(x)
-1(sin-2(x))
\frac{1}{\sqrt{1-x^2}}
7
The derivative of y = ln(x
2
)is . . . .
2
e2x
2/x
2lnx
8
The derivative of y = e
3x
is _____.
3xe3x
e3x
3e3x
3ex
9
The derivative of y = lnx is . . . .
lnx
1/x
x
ex
10
If we use the chain rule to differentiate y = (8x - 5)
2
we get . . .
2(8x - 5) • 8
2(8x - 5)2 • 8
2(8x - 5)
(8x - 5)3
11
The derivative of y = cos(x
2
) is . . . .
sin(x2)
-2xsin(x2)
2xcos(x2)
tan(x2)
12
If we use implicit differentiation to differentiate x
2
+ y
2
= 25 we get . . . .
2x + 2y(dy/dx) = 0
x2 + y2 = 0
2x + 2y = 0
2x + 2y(dy/dx) = 25
13
The derivative of e
x
is ______.
x
ex
xex
e
