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Duplicate of Derivatives of Trig Functions Flashcards | StudBud

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Duplicate of Derivatives of Trig Functions

15 terms·StudBud Administration

Practice derivatives of trig functions, including sin, cos, tan, csc, sec, cot, arccos, arcsin, arctan, arccot, arccsc, and arcsec. #calculus #derivatives

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Questions 15

Answers

1
y = sin^-1x, y' = ?
1/(1-x2)
1/√1+x2
1/√1-x2
1/(1+x2)
2
y = cos(2x), y' = ?
-2sinx
-sin(2x)/2
-sin(2x)
-2sin(2x)
3
y = cosx, y' = ?
sinx
-cosx
sin2x
-sinx
4
y = tan^-1x, y' = ?
1/(1+x2)
1/√1+x2
1/(1-x2)
1/√1-x2
5
y = sec^-1x, y' = ?
1/(|x|√x2-1)
-1/(|x|√x2-1)
1/(|x|√x2+1)
-1/(|x|√x2+1)
6
y = cscx, y' = ?
cscxcotx
-cscxcotx
cotx
cot2x
7
y = cot^-1x, y' = ?
-1/(1+x2)
-1/(1-x2)
1/(1+x2)
1/(1-x2)
8
y = sin(x/2), y' = ?
2cos(x/2)
cos(x/2)
cos(x/2)/2
cosx/2
9
y = cotx, y' = ?
-csc2x
-cscx
csc2x
cscx
10
y = sinx, y' = ?
cos2x
-cosx
cosx
-sinx
11
y = cos^-1x, y' = ?
1/√1-x2
-1/√1+x2
-1/√1-x2
1/√1+x2
12
y = sin(x²), y' = ?
2xcos(x)
2xcos(x2)
cos(x2)
2cos(x2)
13
y = tanx, y' = ?
csc2x
-sec2x
sec2x
secx
14
y = secx, y' = ?
secxtanx
tan2x
tanx
-secxtanx
15
y = csc^-1x, y' = ?
1/(|x|√x2-1)
-1/(|x|√x2-1)
1/(|x|√x2+1)
-1/(|x|√x2+1)