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Duplicate of Duplicate of Basic Derivative Rules Flashcards | StudBud

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Duplicate of Duplicate of Basic Derivative Rules

12 terms·StudBud Administration·34 plays

Quiz over the basic derivative rules including power, product, quotient & chain rules as well as sin, cos, tan #calculus #derivatives

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Questions 12

Answers

1
Find the equation of the tangent line.
vertical line
y = πx
y = 1
y = 0
2
Horizontal tangents?
x = 6, x = -2
x = -6, x = 2
x = 3
x = 3, x = 4
3
Find the derivative
DNE
0
1
pi
4
Find the derivative.
f'(x) = 1/(2x1/2) + 1/(2x3/2)
f'(x) = 1/(2x)1/2 + 1/(2x)3/2
f'(x) = 1/(2x1/2) - 1/(2x3/2)
f'(x) = (1/2)x - (-1/2)x
5
Find the derivative.
f'(t) = -3t2sin(t)
f'(t) = 3t2cos(t) + t3sin(t)
f'(t) = 3t2cos(t) - t3sin(t)
f'(t) = -3t2cos(t) + t3sin(t)
6
Find the derivative.
f'(t) = -3sin(t) - (1/4)cos(t)
f'(t) = 3cos(t) - (1/4)sin(t)
f'(t) = 3sin(t) + (1/4)cos(t)
f'(t) = -3cos(t) + (1/4)sin(t)
7
Find the derivative.
f'(x) = (1/2)/(1 - x3)1/2
f'(x) = (1-x3)1/2
f'(x) = -3x2/[2(1 - x3)1/2]
f'(x) = sqr(-3x2)
8
Find the derivative.
f'(t) = 4/(3t3)
f'(t) = -4/(3t3)
f'(t) = (-4/3)t3
f'(t) = (4/3)t
9
Find the derivative.
f'(x) = 1/(2x)
f'(x) = -x2 + 6x + 1
f'(x) = (-x2 - 6x + 1)/(x2 + 1)2
f'(x) = (-x2 + 6x + 1)/(x2 + 1)2
10
Find the derivative.
f'(x) = 1/(2x1/2) - 12x2 - 3/x2
f'(x) = -1/(2x3/2) - 12x2 - 3/x2
f'(x) = -1/(2x3/2) - 12x2 + 3/x2
f'(x) = x-1/2 - 12x2 + 3x-1
11
Find the derivative.
f'(x) = 2 - 4/x2
f'(x) = 3x - 3 + 2/x
y' = (6x2 - 6x + 4)/(2x)
f'(x) = 2x - 3 + 4/x
12
Find the derivative.
f'(x) = 3x2 - 6x
f'(x) = -3x
f'(x) = 3x2 - 6
f'(x) = 0