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Calculus Chapter 3 Flashcards | StudBud
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Calculus Chapter 3
Calculus Chapter 3
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Calculus -- Derivatives
Flashcards
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Questions
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Answers
1
True or False: A function can be continuous but not differentiable at a point.
True
False
2
This function is not differentiable at x = 0 because there is a . . . .
cusp
vertical tangent
discontinuity
corner
3
Differentiate the function below . . .
y' = cotx
y' = secxtanx
y' = sec2x
y' = -csc2x
4
Differentiate the function below . . .
y' = sec2x
y' = cotx
y' = -csc2x
y' = -cscxcotx
5
The graph of the derivative of the function below would look like . . . .
a parabola
a non-horizontal line
a horizontal line
John Peschel
6
The absolute value of velocity is . . . .
acceleration
nice
negative
speed
7
To differentiate the function y = 2xsinx we have to use the . . . .
Power Rule
Product Rule
Produce Rule
Quotient Rule
8
Differentiate the function below . . .
y' = -cot2x
y' = -csc2x
y' = -sinx
y' = cscxcotx
9
This is the . . . .
Alternate Definition of the Derivative
Quotient Rule
Power Rule
Definition of the Derivative
10
The graph of the derivative of a function f(x) describes the _____ of f(x).
slope
life
asymptotes
symmetry
11
The Quotient Rule: "low d-hi minus hi d-low over ______ squared."
x
high
c
low
12
This function is not differentiable at x = 0 because there is a . . . .
cusp
corner
vertical tangnent
discontinuity
13
Differentiate the function below . . . .
y' = 5x
y' = 4x5
y' = x4
y' = 5x4
14
Differentiate the function below . . .
y' = -3
y' = -6x2
y' = -6x
y' = -3x3
15
Differentiate the function below . . .
y' = -cos2x
y' = cscxcotx
y' = secxtanx
y' = sec2x
16
If s(t) is the position function of an object, the first derivative of s(t) gives us . . . .
velocity
speed
acceleration
a headache
17
If s(t) is the position function of an object, the second derivative of s(t) gives us . . . .
acceleration
2 headaches
velocity
speed
18
This function is not differentiable at x = 0 because there is a . . . .
discontinuity
cusp
vertical tangent
corner
19
Differentiate the function below . . .
y' = sinx + cosx
y' = 7
y' = tanx + cotx
y' = cosx - sinx
20
To find a horizontal tangent to a function f, take its derivative and . . .
run
set it equal to 0
simplify
set it equal to 1