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Duplicate of AP Calculus AB Review
Duplicate of AP Calculus AB Review
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AP Calculus AB Review
Flashcards
42 cards
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Questions
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Answers
1
Choose the correct answer: (d/dx)[cos(u)] =
-sin(u)·u'
cos2(u)·u'
sin(u)·u'
csc(u)·u'
2
Choose the correct answer: (d/dx)[sec(u)] =
-csc(u)cot(u)·u'
sec(u)cot(u)·u'
sec(u)tan(u)·u'
-csc(u)tan(u)·u'
3
Choose the correct answer: ∫cos(x)
dx
sin(x) + C
-sin(x) + C
cot2(x) + C
sec(x) + C
4
What method is used to find volume?
Newton's method
washer or shell method
L'Hopital's method
Pascal's method
5
How do you find the area between two functions of x?
top - bottom
∫(bottom - top)dx
π(top + bottom)
∫(top - bottom)dx
6
Choose the correct answer: ∫(1/x)
dx
x-2 + C
ln∣x∣ + C
2x-2 + C
x<span style="font-size: 13.3333330154419px;">n+1 + C</span>
7
The second derivative of a function provides information about the _______ of that function.
slope
acceleration
speed
concavity
8
Choose the correct answer: (d/dx)[
a
u
] =
au·ln(u)·u'
au·ln(a)·u'
ln(a)·u'
au·u'
9
Choose the correct answer.
6
4
7
2
10
Choose the correct answer: (d/dx)[
e
u
] =
eu + C
ueu
ueu·u'
eu·u'
11
Choose the correct answer.
-6x2sin(x3)
-6x2sin(x3)cos(x3)
6x2sin(x3)cos(x3)
6x2cos(x3)
12
Choose the correct answer: (d/dx)[
vu
] =
(uv') / (vu')
uv' - vu'
u'v'
uv' + vu'
13
Choose the correct answer: (d/dx)[tan(u)] =
sec2(u)·u'
sec(u)·u'
-csc2(u)·u'
csc(u)·u'
14
Choose the correct answer: (d/dx)[
u/v
] =
uv' - vu'
(uv') / (vu')
(vu' - uv')/(v2)
uv' + vu'
15
Choose the correct answer: ∫sin(x)
dx
-cos(x) + C
cos2(x) + C
sin(x)cos(x) + C
cos(x) + C
16
Choose the correct answer: ∫a
x
dx
ax / ln(a) + C
2x-2 + C
xln(a) + C
aln∣x∣ + C
17
Choose the correct answer.
-7/27
7/27
-25/27
25/27
18
Choose the correct answer.
36
4
2
6
19
Choose the correct answer: ∫sec
2
(x)
dx
sin(x)cos(x) + C
sin(x) + C
cot2(x) + C
tan(x) + C
20
Find the lim
x→0
(
sin
x
/ 2x)
0
-2
1/2
-1
21
Choose the correct answer.
8
13
11
14
22
Choose the correct answer: ∫
e
x
dx
xex + C
ex + C
xex
ex
23
Choose the correct answer.
16π/3
32π/5
8π/3
4π/3
24
Choose the correct answer.
x < -1 and x > 3
All values of x
-3 < x < 1
-1 < x < 3
25
Choose the correct answer.
1
-1
-3
3
26
What does the mean value theorem state (for continuous, differentiable functions)?
average slope = instantaneous slope
Average slope < 0
average slope ≠ instantaneous slope
average slope > 0
27
Choose the correct answer: ∫sec(x)tan(x)
dx
tan(x) + C
sec2(x) + C
sec(x) + C
cot2(x) + C
28
Choose the correct answer.
1
0
e+1
e-1
29
The first derivative of a function provides information about the _______ of that function.
slope
speed
acceleration
concavity
30
Choose the correct answer.
y-1 = 2(x - π/4)
y -1= -2(x - π/4)
y = 2(x - π/4)
y = -2(x - π/4)
31
Choose the correct answer: (d/dx)[
ln(u)
] =
ueu·u'
ln(u)·u'
(1/u)∙ln(u)·u'
(1/u)·u'
32
Choose the correct answer: (d/dx)[csc(u)] =
-csc(u)cot(u)·u'
sec2(u)·u'
-csc(u)tan(u)·u'
csc(u)cot(u)·u'
33
Choose the correct answer: (d/dx)[sec(u)] =
sec(u)cot(u)·u'
-csc(u)tan(u)·u'
-csc(u)cot(u)·u'
sec(u)tan(u)·u'
34
Choose the correct answer: ∫csc(x)cot(x)
dx
-cot2(x) + C
sec(x) + C
-csc(x) + C
cot(x) + C
35
To find position from acceleration, you must...
integrate once
find the 1st derivative
integrate twice
find the 2nd derivative
36
Choose the correct answer.
16/3
28/3
14/3
32/3
37
Choose the correct answer: ∫csc
2
(x)
dx
sin(x) + C
-cot(x) + C
-cot2(x) + C
sec(x) + C
38
Choose the correct answer: (d/dx)[cot(u)] =
-csc2(u)·u'
sec(u)tan(u)·u'
sec2(u)·u'
-csc(u)tan(u)·u'
39
Choose the correct answer: (d/dx)[sin(u)] =
tan(u)·u'
-cos(u)·u'
csc(u)·u'
cos(u)·u'
40
To find velocity from position, you must...
integrate once
find the 1st derivative
find the 2nd derivative
integrate twice
41
Choose the correct answer.
e(t/2) + C
e-t + C
e(-t/2) + C
2e(t/2) + C
42
For all related rates problems, you must derive each term with respect to
x
area
time
volume