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Differentiation of Trigonometric functions Flashcards | StudBud

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What must θ be measured in when using calculus on \sinθ and \cosθ and in fact any trigonmetric function?

y=3\cos\left(2\pi x\right),\frac{dy}{dx}=

Differentiation of Trigonometric functions

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Answers

1
y=3\cos\left(2\pi x\right),\frac{dy}{dx}=
\frac{dy}{dx}=-6\pi\sin2\pi x
\frac{dy}{dx}=6\pi\sin2\pi x
\frac{dy}{dx}=-3\sin2\pi x
\frac{dy}{dx}=-6\sin2\pi x
2
What must θ be measured in when using calculus on \sinθ and \cosθ and in fact any trigonmetric function?
It does not matter
degrees
radians
gradians
3
y=\sin\left(bx\right),\frac{dy}{dx}=
\frac{dy}{dx}=b\cos x
\frac{dy}{dx}=b\cos bx
\frac{dy}{dx}=b\cos\left(bx-1\right)
\frac{dy}{dx}=\cos bx
4
y=\sin\left(x\right),\frac{dy}{dx}=
\frac{dy}{dx}=-\sin x
\frac{dy}{dx}=\cos x
\frac{dy}{dx}=\tan x
\frac{dy}{dx}=\sin x
5
To prove the derivatives of \sin x and \cos x from first principles the formulae are in the formula booklet
False
True
6
y=\cos\left(x\right),\frac{dy}{dx}=
\frac{dy}{dx}=\cos x
\frac{dy}{dx}=-\sin x
\frac{dy}{dx}=\tan x
\frac{dy}{dx}=\sin x
7
The derivatives of \sin x and \cos x are in the formula booklet
True
False
8
y=\frac{1}{4}\cos\left(x\right),\frac{dy}{dx}=
\frac{dy}{dx}=-\frac{1}{.4}\sin x
\frac{dy}{dx}=\frac{1}{4}\sin x
\frac{dy}{dx}=\frac{1}{4}\cos x
\frac{dy}{dx}=\frac{1}{4}\tan x
9
y=3\sin\left(x\right),\frac{dy}{dx}=
\frac{dy}{dx}=3\tan x
\frac{dy}{dx}=3\sin x
\frac{dy}{dx}=-3\sin x
\frac{dy}{dx}=3\cos x
10
y=\cos\left(bx\right),\frac{dy}{dx}=
\frac{dy}{dx}=b\sin bx
\frac{dy}{dx}=-b\sin bx
\frac{dy}{dx}=-b\sin x
\frac{dy}{dx}=-\sin bx