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MCV4U Final Exam Review Derivatives Flashcards | StudBud
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MCV4U Final Exam Review Derivatives
MCV4U Final Exam Review Derivatives
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MCV4U Final Exam review #calculus #derivatives
Flashcards
15 cards
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Questions
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Answers
1
Given the function f(x) = cos x
, the derivative f'(x) = ?
cos x
-cos x
sinx
-sin x
2
The point of inflection for a function can be found by
finding the x-intercepts of a function
finding the y-intercept of a function
taking the first derivative and setting it equal to zero
taking the second derivative and setting it equal to zero
3
If the displacement function is given as s(t) = t
4
, then the velocity function is ?
v(t) = 4t3
v(t) = 4t3 + t2
v(t) = 12t2
v(t) = 4t2
4
Determine the maximum and minimum points for f(x) = x
3
- 3x, x∈ [0,2]
(-√3,0) and (√3,0)
(-1,2) and (1,-2)
(1, -2) and (0,0)
(-1, 2) and (0,0)
5
Given the function f(x) = -3x
2
- 2x, , find the derivative f'(x) = ?
-6x2 - 2x
-6x - 2
-2x2 - 2
-2x2 - 2x
6
Given the function f(x) = sin x
, the derivative f'(x) = ?
sin2x
cos x
-cos x
-sin x
7
Given the function f(x) = e
x
, the derivative f'(x) = ?
1
0
f'(x) = ex
1/x
8
Given the function f(x) = sin(4x), the derivative f'(x) = ?
4cos x
4cos(4x)
cos(4x)
-4sinx
9
What is the derivative of the function f(x) = (2x
3
+ 1)
5
?
5(6x2 )4
5(2x3 +1)4
5(2x3 +1)4 (6x2)
2x15 + 1
10
Given the function f(x) = 3
x
, the derivative f'(x) = ?
3ex
x . (3x-1)
x3
ln 3 . (3x)
11
The equation of the tangent line to the curve y = x
2
at the point P(1,1) is
y = 2x + 1
y = 2x - 1
y = 2x
y = -2x -1
12
If the displacement function is given as s(t) = t
4
, then the acceleration function is ?
a(t) = 12t2
a(t) = 4t3 + t2
a(t) = 4t3
a(t) = 4t2
13
For what values of x is f(x) = 0.5(x+2) (x-4)
2
decreasing
0 <x <4
x > -2
x < 0
x < -2
14
Given the function f(x) = e
-x
, the derivative f'(x) = ?
xex
e-x
1
-e-x
15
Given the graph of f(x), what graph could be f'(x)
C
D
B
A