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AP Calculus AB Review KJS - Part 2 Flashcards | StudBud
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AP Calculus AB Review KJS - Part 2
AP Calculus AB Review KJS - Part 2
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AP Calculus AB Review #calculus #math #ap #derivatives #integrals
Flashcards
14 cards
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Questions
14
Answers
1
Choose the correct answer: (d/dx)[sec(u)] =
sec(u)cot(u)·u'
sec(u)tan(u)·u'
-csc(u)tan(u)·u'
-csc(u)cot(u)·u'
2
Choose the correct answer.
6
2
4
7
3
Choose the correct answer: (d/dx)[cos(u)] =
cos2(u)·u'
-sin(u)·u'
sin(u)·u'
csc(u)·u'
4
Choose the correct answer: ∫sin(x)
dx
cos(x) + C
-cos(x) + C
-cos(x)
1/2*sin2(x) + C
5
For all related rates problems, you must derive each term with respect to
x
time
volume
area
6
The first derivative of a function provides information about the _______ of that function.
speed
acceleration
concavity
slope
7
Choose the correct answer.
-7/27
-25/27
7/27
25/27
8
Choose the correct answer: (d/dx)[tan(u)] =
sec2(u)·u'
-csc2(u)·u'
csc(u)·u'
sec(u)·u'
9
Choose the correct answer.
y -1= -2(x - π/4)
y-1 = 2(x - π/4)
y = -2(x - π/4)
y = 2(x - π/4)
10
How do you find the area between two functions of x?
π(top + bottom)
∫(top - bottom)dx
∫(bottom - top)dx
top - bottom
11
Choose the correct answer. USE A CALCULATOR!
-1 < x < 3
All values of x
x < -1 and x > 3
-3 < x < 1
12
Choose the correct answer: ∫csc(x)cot(x)
dx
sec(x) + C
-csc(x) + C
cot(x) + C
-cot2(x) + C
13
Choose the correct answer: (d/dx)[
e
u
] =
eu + C
ueu·u'
eu·u'
ueu
14
Choose the correct answer: ∫sec
2
(x)
dx
tan(x) + C
cot2(x) + C
sin(x) + C
sin(x)cos(x) + C
