HL Calculus #2 Flashcards

1

y= x³ Ln x

yI= x2 + 3x2 Ln x
yI= x2 (1+3Ln x)
yI= x2 - 3x2 Ln x

2

y= x⁵+2x^-3

yI= 5x4+6x-4
yI= 5x4-6x-4
yI= x5 + 2x3

3

y= tan(sin x)

yI= tan x(cos x) + sin x(sec2)
yI= sec2 (sin x)
yI= sec2 (sin x) cos x

4

F(x)= x³/x+4

FI(x)= x3+6/4x+8
FI(x)= 2x3+12x2/(x+4)2
FI(x)= 3x3+12x2-x3/(x+4)2
FI(x)= 2x3-12x2/(x+8x+16)

5

y= (3x+1)²

yI=2(3x+1)
yI=1/3(3x+1)^3
yI=18x+6
yI=6(3x+1)

6

If f(x) = ln(x²), then f '' (4) =

1/2
-1/8
1/8
e2

7

find f'(x)

D
B
A
C

8

Find dy/dx in terms of x and y

D
B
C
A

9

y= Ln((x²)/4(x²-3))

yI=2Ln x - 4 Ln (x2-3)
yI=(2/x)-(8x/x2-3)
yI=2Ln (1/x) - 4Ln (2x/x2-3)
yI=0

10

Find dy/dx in terms of x and y

D
C
B
A

11

Find dy/dx in terms of x and y

D
B
C
A

12

Find dy/dx

D
B
A
C

13

if y=x^x find dy/dx

xx(lnx+x)
xx(lnx+1)
xx(lnx+1+x)
xx(1+x)

14

The graph of y = 5x⁴- x⁵ has a point of inflection at x =

3
4
0 and 3
0

15

y= 3sinx - 4cosx

yI=3cos - 4 -sin x
yI=3cos x + 4sin x
yI= -3cos x - 4sin x
yI= -3cos x + 4sin x

16

Find dy/dx in terms of x and y

D
A
B
C

HL Calculus #2

Questions 16

HL Calculus #2

Questions 16