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Derivatives!
f(x) = x5 + x4 + x3 + x2 + x
f(x) = x(x +1)
Derivatives!
12 terms
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#math #derivatives #calculus
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Answers
1
f(x) = x(x +1)
f'(x) = 2x + 1
f'(x) = 2x
f'(x) = x2 + x
f'(x) = 1
2
f(x) = x
5
+ x
4
+ x
3
+ x
2
+ x
f(x) = x5 + x4 + x3 + x2 + x
f(x) = 4x5 + 3x4 + 2x3 + x2
f'(x) = 5x4 + 4x3 + 3x2 + 2x + 1
f'(x) = 5x4 + 4x3 + 3x2 + 2x
3
f(x) = (2x
2
) / (x
2
)
f'(x) = (4x3) / (x4)
f'(x) = 2
f'(x) = 0
f(x) = 0
4
f(x) = 5x
100
f'(x) = 500x99
f'(x) = 500x101
f'(x) = x500
f'(x) = 500x100
5
f(x) = e
xcos(x)
f'(x) = excos(x)(-xsin(x)+cos(x))
f'(x) = excos(x)
f''(x) = excos(x)(-xsin(x)+cos(x))
f'(x) = excos(x)(-xcos(x)+sin(x))
6
f(x) = tan(x)
f'(x) = sec2(x)
f'(x) = 1/cot(x)
f'(x) = tan(x)sec(x)
f'(x) = sec(x)
7
f(x) = (x
4
)/(2x
2
+ 3x)
f'(x) = (2x5 + 6x4) / (4x4 + 3x3)
f'(x) = (2x5 + 6x4) / (2x4 + 3x3)
f'(x) = 5x3
f'(x) = (3x5 + 6x4) / (2x4 + 3x3)
8
f(x) = e
x
f'(x) = 1
f'(x) = -1
f'(x) = ex
f'(x) = 0
9
f(x) = tan(e
x
) + e
tan(x)
f'(x) = sec2(ex)(ex) + etan(x)(sec2(x))
f'(x) = etan(x)(sec2(x))
f''(x) = sec2(ex)(ex) + etan(x)(sec2(x))
f(x) = sec2(ex)(ex)
10
f(x) = x
2
(x
3
+ x)
f'(x) = 5x4 + 3x2
f'(x) = x
f'(x) = 5x + 2x
f'(x) = x5 + x3
11
f(x) = sin(x), find the third derivative
f'(x) = sin(x)
f'''(x) = -sin(x)
f'''(x) = -cos(x)
f'''(x) = cos(x)
12
y = 2
sinx
y' = sin(x)(cos(x))(ln2)
y' = cos(x)ln2
y' = 2sin(x)(cos(x))(ln2)
y' = 2sin(x)(ln2)
