Home Library Explore SAT

Home Library Explore SAT

11 Derivative Rules 1 Flashcards | StudBud

Explore/11 Derivative Rules 1

11 Derivative Rules 1

10 terms·StudBud Administration·59 plays

Quiz over the basic derivative rules including power, product, quotient & chain rules (a little complex) #calculus #derivative #derivatives #differentiation

Flashcards10 cardsFPractice quizPHost liveL

Questions 10

Answers

1
Find the derivative.
y' = (2x)(x2 - 1)2(4x2 - 1)]
y' = 12x2(x2 - 1)2
Nope
y' = (x2 - 1)2[2x(x2 - 1) + 3x2]
2
Find the derivative.
f'(x) = 1/(2x1/2) - 12x2 - 3/x2
f'(x) = -1/(2x3/2) - 12x2 + 3/x2
f'(x) = -1/(2x3/2) - 12x2 - 3/x2
f'(x) = x-1/2 - 12x2 + 3x-1
3
Find the derivative.
y' = (6x2 - 6x + 4)/(2x)
f'(x) = 2x - 3 + 4/x
f'(x) = 3x - 3 + 2/x
f'(x) = 2 - 4/x2
4
Find the derivative.
f'(x) = (1-x3)1/2
f'(x) = -3x2/[2(1 - x3)1/2]
f'(x) = sqr(-3x2)
f'(x) = (1/2)/(1 - x3)1/2
5
Find the derivative.
f'(t) = 4/(3t3)
f'(t) = -4/(3t3)
f'(t) = (4/3)t
f'(t) = (-4/3)t3
6
Find the derivative
pi
1
DNE
0
7
Find the derivative.
f'(x) = 1/(2x)1/2 + 1/(2x)3/2
f'(x) = (1/2)x - (-1/2)x
f'(x) = 1/(2x1/2) - 1/(2x3/2)
f'(x) = 1/(2x1/2) + 1/(2x3/2)
8
Horizontal tangents?
x = 6, x = -2
x = 3, x = 4
x = 3
x = -6, x = 2
9
Find the derivative.
f'(x) = -3x
f'(x) = 3x2 - 6x
f'(x) = 0
f'(x) = 3x2 - 6
10
Find the derivative.
f'(x) = -x2 + 6x + 1
f'(x) = (-x2 + 6x + 1)/(x2 + 1)2
f'(x) = 1/(2x)
f'(x) = (-x2 - 6x + 1)/(x2 + 1)2