stud
bud
Sign up
Log in
Home
Library
Explore
SAT
More
Equation Vocabulary Flashcards | StudBud
Explore
/
Equation Vocabulary
Equation Vocabulary
14 terms
·
StudBud Administration
·
217 plays
a review of vocab for linear equations
Flashcards
14 cards
F
Practice quiz
P
Host live
L
Questions
14
Answers
1
The slope shown is
-5
negative
steep
cannot be determined
2
In the equation
y= 5x + 6,
the number 5 represents the . . .
vertical change / horizontal change
the initial rate
constant of proportionality
change in x / change in y
3
In the equation shown, after adding on both sides, what would be the second step?
divide both sides by 4/3
multiply both sides by the reciprocal
divide by the reciprocal on both sides
multiply both sides by 3/4
4
Which line shows a non-proportional relationship?
Company D
Company B
Company C
Company A
5
In the equation
y = 5x + 6,
the number 5 does not represent the . . .
initial value
coefficient
slope
constant rate of change
6
What mathematical property is being demonstrated?
Distributive Property
Associative Property
Commutative Property
PEMDAS
7
The dependent variable represents
minutes
total cost of call
cost per minute
Long distance charges
8
If we multiply on one side of an equation, what would we do on the other side?
solve
the inverse of division
multiplex
divide
9
Of the following descriptions of a linear relationship, which is not proportional?
y = kx
a multiplicative relationship
an initial value of zero
a line not through the origin
10
Select the inverse operations, in order, you would use to solve this equation:
division and subtraction
subtraction and division
addition and multiplication
add the opposite
11
Which is not a description of
b
?
x-intercept
initial value
what y equals when x is zero
a constant
12
Can you have a negative slope in a proportional relationship?
yes
Where am I?
What's slope?
no
13
Which is not a description of
m
?
constant of proportionality
constant rate of change
unit rate
vertical change over horizontal change
14
How do we solve equations?
Isolate the variable on both sides using inverse operations
Use inverse operations on both sides to isolate the variable
Universe operations on both sides to insulate the variable
Use inverse operations on the variable side to solve
