stud
bud
Sign up
Log in
Home
Library
Explore
SAT
More
AP CALCULUS - Limits and Derivatives Review Flashcards | StudBud
Explore
/
AP CALCULUS - Limits and Derivatives Review
AP CALCULUS - Limits and Derivatives Review
23 terms
·
StudBud Administration
·
28 plays
#limit #derivativerules #extrema #graphs #particlemotion #apcalculusab
Flashcards
23 cards
F
Practice quiz
P
Host live
L
Questions
23
Answers
1
What is the equation of the tangent line?
B
A
D
E
2
The derivative of velocity is
postition
acceleration
displacement
total distance
3
What is the second derivative?
E
A
B
C
4
Find g'(4).
-72
24
32
-32
5
If f(x) = sin(2x), what is f '' (x)?
cos(2x)
2cos(2x)
-4sin(2x)
-2sin(2x)
6
The zero of a velocity function tells us ...
the total distance traveled
the place where a particle is at rest
where the acceleration of a particle is positive
a critical point of the position function
7
What is the limit?
e
1
1/e
nonexistent
8
a maximum of a function occurs where
f ' (x) moves from negative to positive
f ' (x) moves from positive to negative
f(x) = 0
f '(x) = 0
9
The derivative of (2x + 4)
-1
is
- 2(2x + 4)-2
- (2x + 4)-2
ln(2x + 4)
2ln(2x + 4)
10
What is the acceleration at time t = 4?
-9
-12
12
0
11
What is f ' (x)?
D
C
B
A
12
If the equation of a tangent line is y - 2 = ½(x - 4), what is the equation of the normal line?
y - 2 = - ½(x - 4)
y - 2 = - 2(x - 4)
y - 4 = ½(x - 2)
y + 2 = - 2(x + 4)
13
What is the derivative?
D
B
A
C
14
Which is the graph of the original?
D
C
E
B
15
Find f'(x).
-4xsin2x
2x - 2sin2x
2xcos2x - 2x2sin2x
-2xcos2x + 2x2sin2x
16
At what value does the bug change direction?
2
4
7
6
17
A particle changes direction when ...
a(t) = 0
v(t) changes signs
v(t) = 0
v(t) is positive
18
If the velocity of a function is given by f(x) = 2x
4
- 4, what is the acceleration at time t=1?
4
20
8
-2
19
Which statement is true?
A
D
C
B
20
Find the equation of the tangent line
y -45 = 66(x -3)
y = 66x
y + 45 = (-1/66)(x - 3)
y + 45 = 66(x +3)
21
the integral of velocity tells us ...
total distance
position
acceleration
displacement
22
Find f'(x).
((x^5-x+2)(3x^2) - (x^3+7)(5x^4-1))/(x^3+7)^2
((x^3+7)(5x^4-1)-(x^5-x+2)(3x^2))/(x^3+7)^2
(5x^4-1)/(3x^2)
((x^3+7)(5x^4-1)-(x^5-x+2)(3x^2))/(x^3+7)
23
the derivative of tan(x) is
sec2x
sinx
cosx
-cotx
