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2021 Derivatives Unit 2 Review Flashcards | StudBud
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2021 Derivatives Unit 2 Review
2021 Derivatives Unit 2 Review
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Calculus -- Derivatives
Flashcards
20 cards
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Questions
20
Answers
1
Differentiate the function below . . .
y' = secxtanx
y' = sec2x
y' = -csc2x
y' = cotx
2
Differentiate the function below . . .
y' = cosx - sinx
y' = 7
y' = sinx + cosx
y' = tanx + cotx
3
This is the . . . .
Power Rule
Quotient Rule
Alternate Definition of the Derivative
Definition of the Derivative
4
This function is not differentiable at x = 0 because . . . .
limx→0- f '(x) ≠ limx→0+ f '(x)
limx→0- f(x) ≠ limx→0+ f(x)
limx→0- f(x) ≠ f(0)
limx→0 f '(x)= ∞
5
The graph of the derivative of the function below would look like . . . .
a parabola
a horizontal line
a non-horizontal line
a cubic function
6
If s(t) is the position function of an object, the first derivative of s(t) is ...
a headache
acceleration
velocity
speed
7
Differentiate the function below . . . .
y' = x4
y' = 5x
y' = 5x4
y' = 4x5
8
Differentiate the function below . . .
y' = sec2x
y' = -csc2x
y' = -cscxcotx
y' = cotx
9
To find a horizontal tangent to a function f, take the derivative of f and . . .
simplify
set equal to 1
run
set equal to 0
10
The Quotient Rule: "f'g minus g'f over ______ squared."
f
g
c
x
11
This is the . . . .
Power Rule
Alternate Definition of the Derivative
Quotient Rule
Definition of the Derivative
12
True or False: A function can be continuous but not differentiable at a point.
True
False
13
This function is not differentiable at x = 0 because . . . .
limx→0- f '(x) ≠ limx→0+ f '(x)
limx→0- f(x) ≠ f(0)
limx→0 f '(x)= ∞
limx→0- f (x) ≠ limx→0+ f (x)
14
The graph of the derivative of a function f(x) describes the _____ of f(x).
life
symmetry
asymptotes
slope
15
This function is not differentiable at x = 0 because . . . .
limx→0- f '(x) ≠ limx→0+ f '(x)
limx→0 f(x)= ∞
limx→0 f '(x)= ∞
limx→0- f(x) ≠ limx→0+ f(x)
16
Differentiate the function below . . .
y' = sec2x
y' = cscxcotx
y' = -cos2x
y' = secxtanx
17
True or False: A function can be differentiable but not continuous at a point.
False
True
18
To differentiate the function y = 2xsinx, we have to use the . . . .
Produce Rule
Quotient Rule
Product Rule
Power Rule
19
Differentiate the function below . . .
y' = -sinx
y' = -csc2x
y' = cscxcotx
y' = -cot2x
20
Differentiate the function below . . .
y' = -6x2
y' = -3x3
y' = -6x
y' = -3
