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Geometry Unit 6 Review Flashcards | StudBud
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Geometry Unit 6 Review
Geometry Unit 6 Review
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#trapezoid #kite #rectangle #triangle #parallelogram #area #geometry #math #formulas #quadrilateral
Flashcards
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Questions
25
Answers
1
What is the area of this shape?
10 cm2
25 cm
25 cm2
20 cm
2
What is the circumference of the circle? Use 3.14 for \pi.
52.56 in
58.56 in
48.52 in
56.52 in
3
Find the area of the pink, shaded region
24 cm2
12 cm2
40 cm2
28 cm2
4
Use Pythagorean Theorem to solve for x.
√5
7
5
1
5
What is the area of the circle? Use 3.14 for \pi.
24.14 cm2
25.12 cm2
50.14 cm2
50.24 cm2
6
What is the perimeter?
82 u
37 u
80 u
29 u
7
What is the height of this parallelogram?
2 m
1.8 m
2.5 m
90 degrees
8
What type of special right triangle is this?
30-60-90
45-45-90
9
The converse of the Pythagorean Theorem allows us to ______________________________?
Figure out the altitude of the triangle
Identify the type of triangle
Determine the angles in the triangle
Find the missing side of the triangle
10
Find the area of the irregular figure by splitting it up into two polygons.
not enough information
42 cm2
28 cm2
36 cm2
11
If the AREA of a Parallelogram is 40 ft
2
, and the base is 8 ft, what is the height?
10 ft
5 ft2
5 ft
320 ft2
12
Knowing special right triangles, solve for x.
6\sqrt{2}
12
6
6\sqrt{3}
13
If the frame pieces measure 3ft & 6ft in length, what is the area of the green paper?
4.5 ft2
9 ft2
18 ft
18 ft2
14
What is the area of this shape?
90 degrees
30 cm2
15 cm2
30 in2
15
Find the area of the sector. Use 3.14 for \pi.
80 mm2
12.56 mm2
254.55 mm2
56.52 mm2
16
Use properties of special right triangles to find the value of x.
10\sqrt{3}
5
5\sqrt{3}
5\sqrt{2}
17
Determine if the triangle is acute, obtuse or right.
Acute
Obtuse
Right
18
Find the arc length. Use 3.14 for \pi.
20.2
7.3
6.3
15.7
19
Find the area.
24 sq. in.
29 sq. in.
23 sq. in.
30 sq. in.
20
The area of this shape is
56 cm
32 cm2
19 cm
28 cm2
21
How high up does the ladder reach?
12 feet
18 feet
144 feet
8 feet
22
Use Pythagorean theorem to solve the problem!
4 in
11 in
17 in
13 in
23
Solve for the circumference. Use 3.14 for \pi.
12.56 cm
25. 12
50.24 cm
25.12 cm
24
Use Special Right Triangles to determine the value of x.
3\sqrt{2}
3
9
5\sqrt{3}
25
Solve for the area. Use 3.14 for \pi.
113.04 cm2
33. 45 cm2
28.26 cm2
9. 42 cm2
