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Alg I Ch 2 (L2-1 to 2-4) Solving Multi-step Equations Flashcards | StudBud
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Alg I Ch 2 (L2-1 to 2-4) Solving Multi-step Equations
Alg I Ch 2 (L2-1 to 2-4) Solving Multi-step Equations
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#math #algebra #highschool #equations
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1
What is the 1st step you should do to solve this equation? -6y - 31 = 5
Subtract 31 from each side
Divide by -6 on both sides
Subtract 5 from both sides
Add 31 to both sides
2
Distribute: 2(5x + 10)
7x + 12
10x + 12
10x + 20
10x + 10
3
k + 19 = 10
k = -9
k = 10/19
k = 29
k = 190
4
What is the inverse of multiplication?
Subtraction
Multiplication
Addition
Division
5
2x + 16 = 22
x = 19
x = 0
x = -5
x = 3
6
What is a solution?
The answer to the variable that makes the equation true.
A symbol for an unknown value.
Opposite operations, like add and subtract.
2 mathematical sentences set = to each other.
7
What would you undo first to isolate the variable? 4 - 2x = 10
Subtract 4
Divide by -2
Add 2x
Add 4
8
Solve: x - 7 = -12
Infinite solutions
x= -5
x = 5
x = -19
9
What is the last step you should do to solve the equation?
Divide both sides by -6
Add 6 to both sides
Multiply both sides by -6
Divide both sides by -35
10
Solve: -4y = 24
y = 6
y = -28
y = -6
y = 28
11
7(
s
- 5)
7s - 5
17s - 35
7s + 35
7s + 2
12
To undo an operation in an equation is using _______
inverses
solution
distributive property
equation
13
Solve:\frac{k}{3}=-6
k = 3
k = 18
k = 1/2 or .5
k = -18
14
Solve: x + 4 = -10
x = -14
x = 6
x = -6
x = 14