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Duplicate of Practice with Basic Derivative Rules Flashcards | StudBud

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Duplicate of Practice with Basic Derivative Rules

13 terms·StudBud Administration·45 plays

Quiz over the basic derivative rules including power, product, quotient & chain rules as well as sin, cos, tan

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Questions 13

Answers

1
Find the derivative.
f'(x) = -x2 + 6x + 1
f'(x) = (-x2 - 6x + 1)/(x2 + 1)2
f'(x) = (-x2 + 6x + 1)/(x2 + 1)2
f'(x) = 1/(2x)
2
Find the derivative.
y' = 2 - 2x sec2(x)
y' = 2 - 2x sec(x)tan(x)
y' = 2 - 2xtan(x) - x2sec(x)tan(x)
y' = 2 - 2xtan(x) - x2sec2(x)
3
Find the average rate of change.
-3/2
1
1/2
3/2
4
Find the derivative.
f'(t) = -3t2cos(t) + t3sin(t)
f'(t) = 3t2cos(t) + t3sin(t)
f'(t) = -3t2sin(t)
f'(t) = 3t2cos(t) - t3sin(t)
5
Solve the problem below.
-6
4
-1/6
1/10
6
Find the derivative.
f'(x) = (1-x3)1/2
f'(x) = (1/2)/(1 - x3)1/2
f'(x) = sqr(-3x2)
f'(x) = -3x2/[2(1 - x3)1/2]
7
Find the derivative.
f'(t) = (4/3)t
f'(t) = -4/(3t3)
f'(t) = 4/(3t3)
f'(t) = (-4/3)t3
8
Solve the problem below.
(4x + 6)/√(1 - x⁴ - 6x³ - 9x²)
(2x + 3)/√(1 - x⁴ - 6x³ - 9x²)
(2x + 3)/√(x⁴ + 6x³ + 9x² - 1)
(4x + 6)/√(x⁴ + 6x³ + 9x² - 1)
9
Horizontal tangents?
x = 3, x = 4
x = 6, x = -2
x = 3
x = -6, x = 2
10
Find the derivative.
f'(x) = 2 - 4/x2
f'(x) = 3x - 3 + 2/x
y' = (6x2 - 6x + 4)/(2x)
f'(x) = 2x - 3 + 4/x
11
Find the derivative.
f'(x) = 3x2 - 6x
f'(x) = 3x2 - 6
f'(x) = 0
f'(x) = -3x
12
Solve the problem below.
-1/√(1 - x²)
1/(|x|√(x² - 1))
1/(1 + x²)
1/√(1 - x²)
13
Find the derivative.
Nope
y' = (2x)(x2 - 1)2(4x2 - 1)]
y' = (x2 - 1)2[2x(x2 - 1) + 3x2]
y' = 12x2(x2 - 1)2