If the region between y=5-\frac{2}{3}x and y=1 between 0\le x\le5 is rotated around the line y=1, the volume is...
- \int_0^5\left(5-\frac{2}{3}x-1\right)^2dx
- \int_0^5\left[\left(5-\frac{2}{3}x\right)^2-1\right]dx
- \pi\int_0^5\left(5-\frac{2}{3}x-1\right)^2dx
- \frac{1}{2}\pi\int_0^5\left(5-\frac{2}{3}x-1\right)^2dx