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Duplicate of AP Calculus AB Review
Duplicate of AP Calculus AB Review
41 terms
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AP Calculus AB Review #calculus #math #ap #derivatives #integrals
Flashcards
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Questions
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Answers
1
Choose the correct answer.
-3 < x < 1
-1 < x < 3
x < -1 and x > 3
All values of x
2
Find the lim
x→0
(
sin
x
/ 2x)
0
-1
1/2
-2
3
Choose the correct answer.
2e(t/2) + C
e(-t/2) + C
e(t/2) + C
e-t + C
4
Choose the correct answer: (d/dx)[
ln(u)
] =
ln(u)·u'
ueu·u'
(1/u)∙ln(u)·u'
(1/u)·u'
5
Choose the correct answer: ∫sin(x)
dx
cos2(x) + C
cos(x) + C
sin(x)cos(x) + C
-cos(x) + C
6
To find position from acceleration, you must...
integrate once
find the 2nd derivative
find the 1st derivative
integrate twice
7
What does the mean value theorem state (for continuous, differentiable functions)?
average slope ≠ instantaneous slope
average slope > 0
Average slope < 0
average slope = instantaneous slope
8
How do you find the area between two functions of x?
π(top + bottom)
∫(top - bottom)dx
∫(bottom - top)dx
top - bottom
9
Choose the correct answer: (d/dx)[cot(u)] =
-csc2(u)·u'
sec(u)tan(u)·u'
-csc(u)tan(u)·u'
sec2(u)·u'
10
Choose the correct answer: ∫a
x
dx
ax / ln(a) + C
xln(a) + C
aln∣x∣ + C
2x-2 + C
11
Choose the correct answer.
14
8
11
13
12
Choose the correct answer: (d/dx)[
a
u
] =
au·u'
ln(a)·u'
au·ln(a)·u'
au·ln(u)·u'
13
Choose the correct answer: (d/dx)[
vu
] =
uv' - vu'
(uv') / (vu')
u'v'
uv' + vu'
14
Choose the correct answer.
25/27
-25/27
7/27
-7/27
15
Choose the correct answer: (d/dx)[tan(u)] =
csc(u)·u'
sec2(u)·u'
sec(u)·u'
-csc2(u)·u'
16
Choose the correct answer.
-3
3
1
-1
17
Choose the correct answer: ∫sec(x)tan(x)
dx
sec(x) + C
sec2(x) + C
cot2(x) + C
tan(x) + C
18
Choose the correct answer: ∫(1/x)
dx
2x-2 + C
x-2 + C
x<span style="font-size: 13.3333330154419px;">n+1 + C</span>
ln∣x∣ + C
19
Choose the correct answer: (d/dx)[sin(u)] =
tan(u)·u'
cos(u)·u'
-cos(u)·u'
csc(u)·u'
20
Choose the correct answer: (d/dx)[
u/v
] =
(uv') / (vu')
(vu' - uv')/(v2)
uv' - vu'
uv' + vu'
21
Choose the correct answer: (d/dx)[cos(u)] =
-sin(u)·u'
sin(u)·u'
csc(u)·u'
cos2(u)·u'
22
The first derivative of a function provides information about the _______ of that function.
acceleration
concavity
slope
speed
23
Choose the correct answer.
e+1
e-1
1
0
24
Choose the correct answer: (d/dx)[sec(u)] =
-csc(u)tan(u)·u'
sec(u)tan(u)·u'
sec(u)cot(u)·u'
-csc(u)cot(u)·u'
25
Choose the correct answer.
16π/3
8π/3
32π/5
4π/3
26
Choose the correct answer: ∫sec
2
(x)
dx
sin(x) + C
sin(x)cos(x) + C
tan(x) + C
cot2(x) + C
27
The second derivative of a function provides information about the _______ of that function.
acceleration
concavity
slope
speed
28
To find velocity from position, you must...
integrate twice
find the 2nd derivative
find the 1st derivative
integrate once
29
Choose the correct answer.
4
7
2
6
30
For all related rates problems, you must derive each term with respect to
time
area
volume
x
31
Choose the correct answer: ∫
e
x
dx
xex + C
ex + C
ex
xex
32
Choose the correct answer.
-6x2sin(x3)cos(x3)
6x2sin(x3)cos(x3)
6x2cos(x3)
-6x2sin(x3)
33
Choose the correct answer: (d/dx)[csc(u)] =
-csc(u)tan(u)·u'
-csc(u)cot(u)·u'
csc(u)cot(u)·u'
sec2(u)·u'
34
Choose the correct answer.
y -1= -2(x - π/4)
y = 2(x - π/4)
y-1 = 2(x - π/4)
y = -2(x - π/4)
35
Choose the correct answer: (d/dx)[
e
u
] =
ueu·u'
eu·u'
ueu
eu + C
36
Choose the correct answer: ∫cos(x)
dx
cot2(x) + C
sec(x) + C
sin(x) + C
-sin(x) + C
37
Choose the correct answer.
28/3
32/3
16/3
14/3
38
Choose the correct answer: (d/dx)[sec(u)] =
-csc(u)tan(u)·u'
sec(u)cot(u)·u'
-csc(u)cot(u)·u'
sec(u)tan(u)·u'
39
Choose the correct answer: ∫csc(x)cot(x)
dx
cot(x) + C
sec(x) + C
-csc(x) + C
-cot2(x) + C
40
Choose the correct answer.
6
2
36
4
41
Choose the correct answer: ∫csc
2
(x)
dx
sin(x) + C
sec(x) + C
-cot2(x) + C
-cot(x) + C